Theorem Details
-- De Morgan's law
theorem demorgan_not_or (P Q : Prop) : ¬(P ∨ Q) ↔ (¬P ∧ ¬Q) := by sorry
Bounty: 0.03 ETH
Status: Closed
Proof
open Classical -- De Morgan's law theorem demorgan_not_or (P Q : Prop) : ¬(P ∨ Q) ↔ (¬P ∧ ¬Q) := Iff.intro (fun lhs : ¬(P ∨ Q) => show ¬P ∧ ¬Q from And.intro (fun hp : P => lhs (Or.intro_left Q hp)) (fun hq : Q => lhs (Or.intro_right P hq))) (fun rhs : ¬P ∧ ¬Q => show ¬(P ∨ Q) from fun h : P ∨ Q => Or.elim h rhs.left rhs.right)