Theorem Details
-- De Morgan's law
theorem demorgan_not_or (P Q : Prop) : ¬(P ∨ Q) ↔ (¬P ∧ ¬Q) := by sorry
Bounty: 0.03 ETH
Status: Closed
Proof
open Classical
-- De Morgan's law
theorem demorgan_not_or (P Q : Prop) : ¬(P ∨ Q) ↔ (¬P ∧ ¬Q) :=
Iff.intro
(fun lhs : ¬(P ∨ Q) => show ¬P ∧ ¬Q from And.intro
(fun hp : P => lhs (Or.intro_left Q hp))
(fun hq : Q => lhs (Or.intro_right P hq)))
(fun rhs : ¬P ∧ ¬Q => show ¬(P ∨ Q) from
fun h : P ∨ Q =>
Or.elim h rhs.left rhs.right)